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Coordinate Geometry Class 10 Mathematics Concept notes and Formula Sheet

 

Concepts:

  1. Introduction to Coordinate Geometry:

    • Coordinate Geometry is a branch of mathematics that uses algebraic equations to describe the position of points on a plane.
    • The Cartesian plane consists of two perpendicular lines: the x-axis (horizontal) and the y-axis (vertical).
    • The point of intersection of the x-axis and y-axis is called the origin (0, 0).
  2. Coordinates of a Point:

    • Any point on the plane is represented by an ordered pair (x,y)(x, y), where xx is the abscissa (distance from the y-axis) and yy is the ordinate (distance from the x-axis).
    • The coordinates of the origin are (0, 0).
  3. Distance Formula:

    • The distance between two points P(x1,y1)P(x_1, y_1) and Q(x2,y2)Q(x_2, y_2) is given by: PQ=(x2x1)2+(y2y1)2PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
    • This formula is derived from the Pythagorean theorem.
  4. Section Formula:

    • The coordinates of the point P(x,y)P(x, y) that divides the line segment joining two points A(x1,y1)A(x_1, y_1) and B(x2,y2)B(x_2, y_2) in the ratio m:nm:n are given by: x=mx2+nx1m+n,y=my2+ny1m+nx = \frac{mx_2 + nx_1}{m+n}, \quad y = \frac{my_2 + ny_1}{m+n}
    • If the point divides the line segment internally, use the above formula. If it divides externally, change the sign in the denominator to mnm-n.
  5. Midpoint Formula:

    • The coordinates of the midpoint M(x,y)M(x, y) of the line segment joining two points A(x1,y1)A(x_1, y_1) and B(x2,y2)B(x_2, y_2) are: x=x1+x22,y=y1+y22x = \frac{x_1 + x_2}{2}, \quad y = \frac{y_1 + y_2}{2}
  6. Area of a Triangle:

    • The area of a triangle formed by three points A(x1,y1)A(x_1, y_1), B(x2,y2)B(x_2, y_2), and C(x3,y3)C(x_3, y_3) is given by: Area=12x1(y2y3)+x2(y3y1)+x3(y1y2)\text{Area} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right|
    • The area is positive regardless of the order of the points, but if the area is zero, the points are collinear.
  7. Slope of a Line:

    • The slope (m) of a line passing through two points A(x1,y1)A(x_1, y_1) and B(x2,y2)B(x_2, y_2) is given by: m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
    • The slope indicates the steepness and direction of the line. A positive slope means the line is rising, while a negative slope means it is falling.
  8. Equation of a Line:

    • The general equation of a line in the Cartesian plane is Ax+By+C=0Ax + By + C = 0.
    • The slope-intercept form of a line is: y=mx+cy = mx + c where mm is the slope and cc is the y-intercept.
    • The point-slope form of a line passing through a point P(x1,y1)P(x_1, y_1) with slope mm is: yy1=m(xx1)y - y_1 = m(x - x_1)
  9. Collinearity of Points:

    • Three points A(x1,y1)A(x_1, y_1), B(x2,y2)B(x_2, y_2), and C(x3,y3)C(x_3, y_3) are collinear if the area of the triangle formed by these points is zero. Alternatively, the slope between any two pairs of these points should be equal.

Formula Sheet:

  1. Distance Formula:

    PQ=(x2x1)2+(y2y1)2PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
    • Used to calculate the distance between two points.
  2. Section Formula (Internal Division):

    (mx2+nx1m+n,my2+ny1m+n)\left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n} \right)
    • Used to find the coordinates of a point dividing a line segment internally.
  3. Midpoint Formula:

    M(x1+x22,y1+y22)M\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
    • Used to find the midpoint of a line segment.
  4. Area of a Triangle:

    Area=12x1(y2y3)+x2(y3y1)+x3(y1y2)\text{Area} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right|
    • Used to calculate the area of a triangle formed by three points.
  5. Slope of a Line:

    m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
    • Used to determine the slope of a line.
  6. Equation of a Line (Slope-Intercept Form):

    y=mx+cy = mx + c
    • Used to express a line's equation when the slope and y-intercept are known.
  7. Equation of a Line (Point-Slope Form):

    yy1=m(xx1)y - y_1 = m(x - x_1)
    • Used to express a line's equation when the slope and a point on the line are known.
  8. Collinearity Condition:

    • Points A(x1,y1)A(x_1, y_1), B(x2,y2)B(x_2, y_2), and C(x3,y3)C(x_3, y_3) are collinear if: Area of ABC=0\text{Area of } \triangle ABC = 0 or Slope of AB=Slope of BC\text{Slope of } AB = \text{Slope of } BC

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