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Class 9 Mathematic Surface Areas and Volumes All Formula & Concept Notes | Formula Sheet

I can provide a detailed overview of the formulas and concepts for Surface Areas and Volumes in Class 9 Mathematics. This topic typically covers the surface areas and volumes of various solid figures such as cubes, cuboids, spheres, cylinders, and cones. Here’s a breakdown:

1. Cube

  • Surface Area: The surface area of a cube is the total area of all six faces.

    Surface Area=6a2\text{Surface Area} = 6a^2

    where aa is the length of an edge.

  • Volume: The volume of a cube is the amount of space enclosed within it.

    Volume=a3\text{Volume} = a^3

    where aa is the length of an edge.

2. Cuboid

  • Surface Area: The surface area of a cuboid is the sum of the areas of all six faces.

    Surface Area=2(lb+bh+lh)\text{Surface Area} = 2(lb + bh + lh)

    where ll is the length, bb is the breadth, and hh is the height.

  • Volume: The volume of a cuboid is the amount of space enclosed within it.

    Volume=l×b×h\text{Volume} = l \times b \times h

    where ll, bb, and hh are the length, breadth, and height, respectively.

3. Sphere

  • Surface Area: The surface area of a sphere is the total area of its curved surface.

    Surface Area=4πr2\text{Surface Area} = 4\pi r^2

    where rr is the radius.

  • Volume: The volume of a sphere is the amount of space enclosed within it.

    Volume=43πr3\text{Volume} = \frac{4}{3}\pi r^3

    where rr is the radius.

4. Cylinder

  • Surface Area: The surface area of a cylinder includes the area of the two circular bases and the rectangular side.

    Surface Area=2πr(h+r)\text{Surface Area} = 2\pi r(h + r)

    where rr is the radius of the base and hh is the height.

  • Volume: The volume of a cylinder is the amount of space enclosed within it.

    Volume=πr2h\text{Volume} = \pi r^2 h

    where rr is the radius of the base and hh is the height.

5. Cone

  • Surface Area: The surface area of a cone includes the area of the base and the lateral surface area.

    Surface Area=πr(r+l)\text{Surface Area} = \pi r (r + l)

    where rr is the radius of the base and ll is the slant height.

  • Volume: The volume of a cone is the amount of space enclosed within it.

    Volume=13πr2h\text{Volume} = \frac{1}{3} \pi r^2 h

    where rr is the radius of the base and hh is the height.

6. Hemisphere

  • Surface Area: The surface area of a hemisphere includes the curved surface area and the area of the base.

    Surface Area=3πr2\text{Surface Area} = 3\pi r^2

    where rr is the radius.

  • Volume: The volume of a hemisphere is half the volume of a sphere.

    Volume=23πr3\text{Volume} = \frac{2}{3} \pi r^3

    where rr is the radius.

These formulas and concepts form the basis for solving problems related to surface areas and volumes in Class 9 Mathematics.

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